"A person's mind, once stretched by a new idea, never regains its original dimensions." Oliver Wendell Holmes
Answers to Text Book Assignments and Note Packets will be placed on this page.
Reminder to email me at wdwyer@mtsinai.k12.ny.us - Include name in subject line
Answers to Text Book HW Below! Remember PP Answers are in the BACK of Text Book!
Remember to SHOW ALL WORK for FULL Credit!
27HW22-TB p219#34,p269#43-45,p335PP1-7 due Wed 03-18-20 10pts. Answers.
p219#34 b. 780 kg-m/s c.d. -780 kg-m/s e. 780 kg-m/s f. 6.1 m/s
p269#43-45 43abc all 255000000 J 43d. 143 m/s 44. 66 m 45ab. -345 J 45c. 34.5 m
31HW23-TB p219#35-36,p270#47-49,p337PP8-10 due Wed 03-25-20 10pts. Answers.
p219#35-36 35e. 0.16 m/s 36. 11 m/s
p270#47-49 47.130 J 48. -2780 J 49. 3400 J
35HW24-TB p219#37,40,p270#50-52,p344-345#1-6 due Wed 04-01-20 10pts.
p219#37) 10.6 m/s 40)0.22 m/s in the original direction
p270#50) 20.0 m 51) 16.8 J 52) 0.102-kg
p344-345#1-6 Read the Text Book to answer.
38HW25-TB p270#53,55,57,59,p345#7-12 due Wed 04-08-20 10pts.
p270# 53) 170 J 55) ab -144000 J c) -288000 N 57)abc 5000 J 59) a 42 m/s b 90. m
p345#7-12 Read the Text Book to answer.
42HW26-TB p270-271#54,56,58,62,65,66,68 due Wed 04-15-20 10pts.
p270#54a) 3900 N 54b) 86000 J 56) 26 m 58ab) 20000 J 58c) 40 m/s
62a) 15.5 kg m/s , -15.5 kg m/s 62b) 2.40 x 10^3 J, 4.00 J
65a) 7700 J 65b) 350 N 66a) 3.4 m/s 66b) 160 J 68) 1200 J
02HW27-TB p343SR1-4,p345-346#13-15,32-34 due Wed 04-22-20 10pts.
#1 frequency
#2 UP wave plus UP wave gives you a bigger UP wave because parts add up.
when the UP wave meets a DOWN wave the wave will be smaller because parts cancel out.
#4 Low frequency (longer wavelength) because the smaller the wavelength the smaller the diffraction.
05HW28-TB p345-346#16-18,21-22,35-39 due Wed 04-29-20 10pts.
35a)2.4m/s 35b)2.9m 36)6.0x10^-7 m 37a)190m to 550m
38a)1.50 x 10^3 m/s 38b)1.00x10^-6 s 38c)1.00x10^-6 s T and f remain unchanged
For 38-First convert the mm to meters. Use the equation speed is equal to frequency times wavelength. Period is equal to 1/frequency. Frequency and period remain the same as you go from one medium to another.
39a) 470 Hz 39b) 240 complete waves 39c)170m
11HW29-TB p346#40,41,p352PP1-3,p368#1-8 due Wed 05-06-20 10pts.
40)1350m 41a) 1/4 b) 0.72s c) 1.4 Hz
19HW31-TB p411#31-33,p478#20,21,24,25,p484PP1-3 due Wed 05-20-20 10pts.
31a)53 degrees b)106 degrees 32)108 degrees 33)1.46
24)1.0x10^-8N away 25)90.N toward
24HW32-TB p412#34,35,p478#26,27,p493PP5-8,p511PP1-4 due Wed 05-27-20 10pts.
34)a 1.33 b water 35) 34.7 degrees 26) 560N 27) 1.5x10*-14 m
Answers to Physics Notes Below! Remember to SHOW ALL WORK for FULL Credit!
Physics Notes-Mechanics- Energy-Conservation, Hooke’s Law
123) 567 J 4) 2.00m 5)228 J 6) 152J 7ab) 1.84 J 7c) 3.84m/s
8ab) 2340000 J 8c) 47.0 J 8d)25.7 m 8e) 41.3 m/s
9) 14.6 m/s 10) 33.4 m 11ab) 283 J 11cd) 141 J 11d) 7.89 m/s
Hooke’s Law (Spring Force) 1) 0.35m 2) 14 N 3) 0.36 m
4a) 65.4 N/m 4b) 11.772 J 5a) 19.6 N 5b) 0.145 m 5c) 1.43 J
Physics Notes-Waves-Introduction to Waves
1) 0.25 s 2) 0.100 Hz 3) 0.40 s 2.5 Hz 4 and 5) Look at Notes!
6) 200. Hz 7) a 1.30 m b 1.36 m explain
8) 5.71 x 10^14 Hz 9) 830 m/s Complete CHART!
Physics Notes-Waves-Light, Reflection, Refraction
1) Green, 5.50 x 10^-7 m 2) 4.29 x 10^14 Hz 3) Draw diagram 4) Draw Normal, construct and measure angle from normal! Then construct reflected ray. incident and reflected angles should be equal A) 1.5 B) 1.88 x 10^8 m/s C) 532nm D) 6.00 x 10^7m/s
E) 1.92 Zircon F) TOWARDS G) AWAY H) 22.1 degrees I) 71.9 degrees
J) 1.54 Sodium Chloride K) 28.9 degrees and construct on diagram
L) Corn oil n=1.47 23 degrees in corn oil. Comes back out at 35 degrees.
Make sure your calculator is set for degrees when making calculations. You also need to use your ruler and protractor very carefully and remember to measure all angles from the normal.
Physics Notes EM 1 Electrostatics Intro
Physics Notes-EM-Electrostatics Introduction
Q = n e
Q stands for the total charge in coulombs.
n is the number of elementary charges.
e is the elementary charger from reference table 1.60 x 10 ^ -19 coulombs.
Some selected answers! Please be sure you show all work and understand all questions!
4.) A positively charged glass rod attracts object X. The net charge of object X
(1)may be zero or negative
6.) Sphere A contains a charge of +6e while Sphere B contains a charge of -4e.
a.) What is the net charge on the entire system? +2e
b.) Sphere A now comes into contact with Sphere B, determine the new charge on each Sphere. +1e
c.) Did Sphere A gain or lose electrons? gain How many? 5e
d.) Did Sphere B gain or lose electrons? lose How many? 5e
7.) Sphere A has a charge of +2e, Sphere B has a charge of -8e, and Sphere C has a charge of -6e. a.)-2e b.) -5e c.) -12e remains the same
8.) a.) +5e b.) gain 11 loss 9 loss 2
Read your Review Book pages 114-120
Just take a look at your review book diagrams of the electric fields on page 119!
Physics Notes EM 2 Electrostatics Fe Electric Fields
Some selected answers! Please be sure you show all work and understand all questions!
5) +7.2x10^-1N 6) -5.4x10^-4N 7) 0.184m 8) 93.1uC
9 and 10 use your physics reference table and distance is 5.2 * 10^-11 m
Just take a look at your review book diagrams of the electric fields on page 119!
7) 6.25x10^19 N/C 8) 6.3x10^18 N/C 9) 0.800N 10) 6.40x10^-19C
Physics Notes-EM 3 Electricity-Ohm’s Law, P, Energy
Some selected answers! Please be sure you show all work and understand all questions!
3) 60.0 ohms 4) 0.369 A 5) 100. V 6) 2880 W 7) 192 W 8) 2.454 A 9) 44.7 V
9) 2.40 x 10^6 J 10) 83.3 s 11) 288000 J 12) 5.4000 x 10^10 J 13) 0.02315 A
Sorry I went out of order. I added this here.
Physics Notes-EM 3A Electrostatics-Electric Potential
Some selected answers! Please be sure you show all work and understand all questions!
1) 1.5 V 2) 6.0V 3) a 3.20 x10^-18 J b E=KE=1/2mvv=solve for v 2.65 x 10^6 m/s
4) 6.72 x 10^-18 C 12) a 3.84 x 10^-18 J b 24.0 eV c 2.90 x 10^6 m/s
Physics Notes-EM 4 Electricity-Current, Resistance
Some selected answers! Please be sure you show all work and understand all questions!
1) 4.0 A 2) 1.20 x 10^4 C 3) 6.0 s 4) 8.00 C = 50.0 x 10^18 electrons
3) Convert mm to m. find A then calculate. 2.05 x 10^-3 ohms
4) 4009m 7) 4.88 x 10^-7 mxm
Physics Notes-EM 5 E&M-Electricity-Series and Parallel Circuits
Some selected answers! Please be sure you show all work and understand all questions!
4a) 48 Ohms 4b) 4.36 Ohms 5a) 30.0 Ohms 5b) 6.67 Ohms 6) choice 4
7)16.0 Ohms 0.75 A 8) V=IR 30.0 Ohms 2.5 V 9) Choice 4 – 7A in and 7A out
10) (4) 5 A toward Q 11) Find the total resistance first then use Ohm’s Law. All I’s equal.
12) Find the total resistance first then use Ohm’s Law. All V’s are equal!
Physics Notes-EM 6 E&M-Magnetism
Some selected answers! Please be sure you show all work and understand all questions!
This should be easy!
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