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Solving for a variable - Step in solving by substitution - (Version 2)

For each equation match the equation that solves for x

AB
2y + x = 10x = -2y + 10
x + 4 = 3yx = 3y - 4
x - y = 10x = y + 10
2x - y = -10x = 1/2y - 5
y - 4 = xx = y - 4
2y + x = 5x = -2y + 5
y + 2x = 10x = -1/2y + 5
5x + 2y = 10x = -2/5y + 2
2y - 5x = 10x = 2/5y - 2
5y + 2x = 10x = -5/2x + 5
-2x + 5y = 10x = 5/2y - 5
x + 10 = yx = y - 10
y - x = 10x = y - 10
x - y = 10x = y + 10
3x + 4y = 12x = -4/3y + 4
3x - 4y = 12x = 4/3y + 4
3x + 4y = -12x = -4/3y - 4
3x - 4y = -12x = 4/3y - 4
3y - x = 5x = 3y - 5
3y + x = 5x = -3y + 5
x + y = 3x = -y + 3
x - y = 3x = y + 3


8th Grade Science and Algebra Teacher
Mansfield Middle School
Storrs, CT

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