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Solving for a variable - Step in solving by substitution - (Version 2)
For each equation match the equation that solves for x
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| A | B |
| 2y + x = 10 | x = -2y + 10 |
| x + 4 = 3y | x = 3y - 4 |
| x - y = 10 | x = y + 10 |
| 2x - y = -10 | x = 1/2y - 5 |
| y - 4 = x | x = y - 4 |
| 2y + x = 5 | x = -2y + 5 |
| y + 2x = 10 | x = -1/2y + 5 |
| 5x + 2y = 10 | x = -2/5y + 2 |
| 2y - 5x = 10 | x = 2/5y - 2 |
| 5y + 2x = 10 | x = -5/2x + 5 |
| -2x + 5y = 10 | x = 5/2y - 5 |
| x + 10 = y | x = y - 10 |
| y - x = 10 | x = y - 10 |
| x - y = 10 | x = y + 10 |
| 3x + 4y = 12 | x = -4/3y + 4 |
| 3x - 4y = 12 | x = 4/3y + 4 |
| 3x + 4y = -12 | x = -4/3y - 4 |
| 3x - 4y = -12 | x = 4/3y - 4 |
| 3y - x = 5 | x = 3y - 5 |
| 3y + x = 5 | x = -3y + 5 |
| x + y = 3 | x = -y + 3 |
| x - y = 3 | x = y + 3 |
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8th Grade Science and Algebra Teacher |
Mansfield Middle School |
| Storrs, CT |
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