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ALGEBRA I-SOLVING SIMPLE EQUATIONS WITH ONE UNKNOWN-PRACTICE EXPERCISES

THE STUDY BUDDY, INC.
SAINT PETERSBURG, FLORIDA 33707

AB
Solve for x and check: cx = a + bSOLUTION: 1) divide both sides by x to solve for x 2) then put ax/c + b/c under a common demonimator which would be c which will give you the solution for x ANSWER: x = a + b / c CHECK: When one substitutes a + b/c for x they reach the equality of a + b = a + b - which indicates the answer is correct.
Solve for x and check: 3x - 4 = 2x + 2SOLUTION: 1) add - 2x to both sides in order to get all x's on one side of the equation 2) add a + 4 to both sides of the equation in order to isolate x on one side of the equation - which then solves for x ANSWER: x = 6 CHECK: When one substitutes 6 in for x, then one obtains the equality of 14 = 14 - which indicates the answer is correct.
Solve for y and check: 4(3y -3) = 2y - 6SOLUTION: 1) break down the parenthesis by multiplying 4 times 3y -3 - which is 12y - 12 2) then add a - 2y to both sides of the equation in order to get all the y's on one side of the equation 3) then add +12 to both sides of the equation in order to isolate y on one side of the equation 4) then divide both sides of the equation by 10 in order to get y by itself on one side of the equation (reduce answer to the lowest terms) - thus, completing the solution for y ANSWER: y = 3/5 CHECK: When one substitutes 3/5 for y, then one obtains the equality of - 24/5 = - 24/ 5 - which indicates the answer is correct
Solve for x and check: 2(1/2x - 2) = 4(-1/4x + 1)SOLUTION: 1) break down the parenthesis on the left side of the equation by multiplying 2 times 1/2x - 2 - which is x - 4 2) then break down the parenthesis on the right side of the equation by multiplying 4 times -1/4x + 1 - which is -x + 4 3) then add a x to both sides of the equation in order to get all the x's on one side of the equation 3) then add + 4 to both sides of the equation in order to isolate x on one side of the equation 3) then divide both sides of the equation by +2 in order to get x by itself on one side of the equation - thus, completing the solution for x ANSWER: x = 4 CHECK: When one subustitutes 4 in for x, one obtains the equality of 0 = 0 - which indicates the answer is correct
Solve for a and check: 2a + 2 - 4a - 3 = -2(6a - 4)SOLUTION: 1) combine all like terms on the left side of the equation - which would then be - 2a - 1 2) then break down the parenthesis on the right side of the equation by multiplying -2 times 6a - 4 - which would then be -12a + 8 3) then add a +12 to both sides of the equation in order to get all the a's on one side of the equation 4) then add a +1 to both sides of the equation in order to islate a on one side of the equation 5) then divide both sides of the equation by 10 in order to get x by itself on one side of the equation - thus, completing the solution for a ANSWER: a = 9/10 CHECK: When one substitutes in for a 9/10, then one obtains an equality of - 28/10 = - 28/10 - which indicates the answer is correct.
Solve for b and check: 7b -9 = -3b + 11SOLUTION: 1) add + 3b to both sides of the equation in order to bring all the b's to one side of the equation 2) then add + 9 to both sides of the equation in order to isolate b 3) then divide both sides of the eqaution by 10 in order in order to get b by itself on one side of the equation - thus, completing the solution for b ANSWER: b = 2 CHECK: When one substitutes 2 in for b, then one obtains the equality of 5 = 5 - which indicates that the answer is correct.
Solve for x and check: 2.5 x - .25 = -3x + .85SOLUTION: 1) add -3x to both sides of the equatin in order to get all the x's to one side of the equation 2) then add +.25 to both sides of the equation in order to get x by itself on one side of the equation 3) then divide both sides of the equation by 5.5 in order to get get all by itself on one side of the equation - thus, completing the solution for x ANSWER: x = .02 CHECK: Whrn one substitutes .2 for x, then one obtains the equality of .25 = .25, which indicates the answer is correct.


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Saint Petersburg, FL

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