| A | B |
|---|
| SPEED | divide the distance the object travels by the amount of time it takes to travel that distance |
| VELOCITY | speed in a given direction |
| MOTION | An object's change in position relative to a reference point. |
| SPEED | Distance an object travels per unit of time |
| DISTANCE | how far an object has moved |
| DISPLACEMENT | distance and direction of an objects change in position from the starting point |
| SPEED FORMULA | speed=distance/time |
| CONSTANT SPEED | speed that doesnt change over time |
| INSTANTANEOUS SPEED | speed at any given point in time |
| VELOCITY | speed and direction of a objects motion |
| REFERENCE POINT | object that appears to stay in place (background) |
| DISTANCE & TIME | 2 things you must know to determine speed |
| SPEED | 80.00 km/hr |
| VELOCITY | 85.00 km/hr south |
| UNITS FOR SPEED | m/s or km/hr |
| MOTION | This can be described as a change in position. & Reference p |
| SPEED | is the rate of change in position |
| CONSTANT SPEED | Speed that does not vary Ex. train @ 60mph for 3 hours |
| AVERAGE SPEED | the distance traveled divided by the total time of travel |
| VELOCITY FORMULA | v = d/t |
| DISPLACEMENT | the change in position of an object from one point to another in a straight line with direction |
| MOTION | Occurs when there is a change in position of an object with respect to a reference starting point. |
| DISPLACEMENT | The change in position is determined by the distance and direction of an object from the starting point to the ending point. |
| F: D/T W: 36 KM / 6 HRS A: 6.00 KM/HR | DISTANCE = 36 KM TIME = 6 HRS |
| same direction --> 7 km + 5 km = 12.00 km north | calculate displacement for Steve traveling 7 km north. He then stopped and rested. After 15 minutes, Steve traveled 5 km farther north. |
| F: S x T W: 3 hrs x 80 km /hr A: 240.00 km | Determine distance if time is 3 hours and speed is 80 km/hr. |
| units for distance | meters or kilometers |
| F: v = d/t W: 150 km / 3 hrs A: 50.00 km/hr to St. Louis | Calculate velocity if traveling towards St. Louis which is a distance of 150 km and takes 3 hours. |
| DISPLACEMENT | straight line distance pointing from where you started to where you ended. |
| units for time | seconds or hours |
| opposite direction --> 60 km - 15 km = 45.00 km west | Determine displacement when Jane travels 60 km west and then turns around and travels 15 km east |
| F: D/S W: 40 m / 5 m/s A: 8.00 s | Determine time if distance is 40 m and speed is 5 m/s |
| F: a2 + b2 = c2 W: (6)^2 km + (4)^2 km A: 7.21 km NW | Calculate displacement if Jerry travels 6 km north and then turns and travels 4 km west. |
