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Java Games: Flashcards, matching, concentration, and word search. |
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FCAT PREPARATION-MATHEMATICS-9TH GRADE-PRACTICE EXERCISES
THE STUDY BUDDY, INC.
SAINT PETERSBURG, FLORIDA
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| If only 2/3's of the students passed on a Biology examination but 1/4 passed on the retest, what is the probability that a student in that class will pass the examination on the retest ? | ANSWER: 1/12 SOLUTION: (1) In order to find out how many students failed the Biology examination, one will subtract 2/3's from 1: therefore, this will result in that 1/3 of the students failed the Biology examination. (2) Then, since 1/4 of the students passed on the retest, then one needs to multiply 1/3 by 1/4 in order to determine the probability of how many students will pass on the retest form those who failed on the first try: therefore, this will result in a probability of 1/12 of the failed students passing the Biology examination on the retest. |
| If there are 45 ball in a given bag and 11 are blue, 10 are green, 8 are red, 12 are yellow, and 3 are white, what is the probability, in percent, that one would pull out a yellow ball from the bag on the first try ? | ANSWER: 26.67% SOLUTION: (1) Since there are 45 total balls in the given bag and 12 of them are yellow, one would set up a proportion of 12/45 in determining the probabilty of pulling a yellow ball out of the bag on the first try. (2) Then, one would divided 12 by 45 in order to determine the probability in a percent; therefore the probality that one would pull out a yellow ball from the given bag on the first try is 26.67%. |
| Harry tosses three (3) dimes and two (2) nickels. What is the probability that two (2) of the nickels will be tails and one (1) of the dimes will also be tails ? | ANSWER: 3/8 SOLUTION: (1) First, construct two tables for all the possible outcomes - one being for dimes and one being for nickels. After this is completed, one can conclude that the possibility for two (2) of the nickels to be tails is 3 out or 4 and for the possibility for one (1) dimes to be tails is 4 out of 8. (2) Finally, to find out the probability of having two (2) of the nickels to be tails and one (1) of the dimes is obtained by multiplying together both of their probabilities; therefore, 3/4 times 1/2 (4/8's reduced) will result in a probability that their is an 3 out of 8 chance that on tossing the coins that two (2) nickels will be tails and one (1) dime will also be tails. |
| It two (2) cylinders, one with a radius of 5 yards and a height of 25 yards and the other having a radius of 4 yards and a height of 20 yards, are joined together to form a massive column, what will be its weight in tons if one (1) yard cubed weights 50 lbs. ? | ANSWER: 74.16 tons SOLUTION: (1) First, determine the volumn of each of the cylinders by using the following formula for the column of a cylinder: v = pie times the radius squared times the height; therefore, the volumn of the first cylinder will be 1962.5 yards cubed and the volumn of the second cylinder will be 1004.8 yars cubed. (2) Next, in order to find out the total volumn of the entire structure, one adds the two volumns of each cylinder together which will result in 2967.3 cubed yards. (3) Then, in order to find the weight of the entire structure one whould multiply the weight of each cubic yard with the volumn of the entire structure; therefore, 50 lbs. times 2967.3 cubic yards which will result in a weight of the entire structure being 148,365 lbs (4) Finally, because there are 2000 lbs. in a ton, one would divided 148,365 lbs. by 2000 lbs in order to convert the weight of the column to tons; therefore, the massive column weights 74.18 tons. |
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The Learning and Tutoring Center, Inc. |
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