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Divisibility by 2,3.4,5,6,8,9,10

AB
Is 260 divisible by 3?No, because the sum of the digits is 2+6+0=8.
Is 5,465 divisible by 5Yes, because the one's is a 5 (0 or 5).
Is 100,012 divisible by 10?No, because the one's digit is not a 0.
Is 78,154 divisible by 9?No, because the sum of the digits is 7+8+1+5+4=25, which is not divisible by 9.
Is 25,489,536 divisible by 2?Yes, because the one's digit is a 6, which is even.
Is 592,388 divisible by 4?Yes, because the last two digits 44, are divisible by 4.
Is 592,388 divisible by 8?No, because the last three digits, 388, are not divisible by 8. (388/8 has a remainder)
Is 592,388 divisible by 6?No, because the sum of the digits is 5+9+2+3+8+8=35, which is not divisible by 3. Any number that is divisible by 6 must be divisible by BOTH 2 AND 3.
Is 735 divisible by 2?No, because the one's digit is not even.
Is 735 divisible by 3?Yes, because the sum of the digits is 7+3+5=15, which is divisible by 3.
Is 735 divisible by 4?No, because the last two digits, 35, is not divis
Is 735 divisible by 5?Yes, because the one's digit is a 0 or 5.
Is 735 divisible by 6?No, because 735 is not divisible by both 2 and 3.
Is 735 divisible by 8?No, because when you divide 735 by 8, there is a remainder.
Is 735 divisible by 10?No, because the one's digit is not a 0.
Is 53,280 divisible by 2?Yes, because the one's digit is 0 which is even.
Is 53,280 divisible by 3?Yes, because the sum of the digits is 5+3+2+8+0=18 which is divisible by 3.
Is 53,280 divisible by 4?Yes, because the last two digits, 80, form a number that is divisible by 4.
Is 53,280 divisible by 5?Yes, because the one's digit is a 0. (either 0 or 5 work)
Is 53,280 divisible by 6?Yes, because 53,280 is divisible by BOTH 2 AND 3.
Is 53,280 divisible by 8?Yes, because 280/8 is exactly 35 (there's no remainder).
Is 53,280 divisible by 9?Yes, because the sum of the digits 5+3+2+8+0=18 which is divisible by 9.
Is 53,280 divisible by by 10?Yes, because the one's digit is a 0.
Is 9,527 divisible by 2?No, because the one's digit, 7, is not even.
Is 9,527 divisible by 3?No, because the sum of the digits is 9+5+2+7=23, which is not divisible by 3.
Is 9,527 divisible by 4?No, because the last two digits, 27, form a number which is not divisible by 4.
Is 9,527 divisible by 5?No, because the one's digit is not a 0 or 5.
Is 9,527 divisible by 6?No, because the number is not divisible by BOTH 2 AND 3.
Is 9,527 divisible by 8?No, because the last three digits form a number that is not divisible by 8.
Is 9,527 divisible by 9?No, because the sum of the digits is 9+5+2+7=23, shich is not divisible by 9
Is 9,527 divisible by 10?No, because the one's digit is not a 0.
Is 8,106,705 divisible by 2?No, becasue the one's digit is not even.
Is 8,106,705 divisible by 3?Yes, because the sum of the digits is 8+1+0+6+7+0+5=27 which is divisible by 3.
Is 8,106,705 divisible by 4?No, because the last two digits, 05, form a number that is not divisible by 4.
Is 8,106,705 divisible by 5?Yes, because the one's digit is a 5 (0 or 5 both work)
Is 8,106,705 divisible by 6?No, because the number is not divisble by both 2 and 3.
Is 8,106,705 divisible by 8?No, because the number formed by the last three digits, 705, is not divisible by 8.
Is 8,106,705 divisible by 9?Yes, because the sum of the digits 8+1+0+6+7+0+5=27 which is divisible by 9.
Is 8,106,705 divisible by 10?No, because the one's digit is not a 0.
Is the number 732 divisible by 2?Yes, because the one's digit is even.
Is the number 732 divisible by 3?Yes, because the sum of the digits is 7+3+2=12 is divisible by 3.
Is the number 732 divisible by 4?Yes, because the last two digits, 32. form a number that is divisible by 4.
Is the number 732 divisible by 5?No, because the one's digit is a 2 (not a 0 or 5).
Is the number 732 divisible by 6?Yes, because the number is divisible by BOTH 2 AND 3.
Is the number 732 divisible by 8?No, because 732/8 has a remainder of 4.
Is the number 732 divisible by 9?No, because the sum of the digits 7+3+2=12, which is not divisible by 9.
Is the number 732 divisible by 10?No, because the one's digit is a 2 (not 0).
Is 111,111,111 divisible by 9?Yes, because 1+1+1+1+1+1+1+1+1=9, which is divisible by 9.
Is 823,501,784,022 divisible by 6?Yes, because the number is divisible by both 2 (its even) and 3 (the sum of the digits is 36).
Is 20,000 divisible by 8?Yes, because the last 3 digits, 000, form a number that is divisble by 8 (0/8=0 with no remainder)

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